1) Ground units below Ships, above Improvements,
2) In same Project Type, sorted by [Buy] value, Cheapest at top, Expensive below.
For detailed ranting, read on. Cheers!
============
I've been trying to change the Left Panel to show the planets in their appropriate sort order, like 'building' of ground units IMO should appear at the top (currently ground units are below improvements) next to the ship building.
\Lua state\GUI\~GalaxyMap\@PlanetListPanel.lua
Code: Select all
local project_order = {
'refitting',
'building_design',
'building_ground_unit', --moved here
'building_improvement',
'building_colony',
'building_planet',
'terraforming',
--'activity',
}I forgot what is the original, I only remembered I edited/changed the line to use project_type(), and add a new function to return buycost so each 'type' say 'mining' list the 'cheapest to [buy]' projects at the top with 'most expensive' at bottom. Another simple function to return just 1st 10 chars of project_name, so for "Colonize: ~~~~~" will return without the colony name.
Hope this can help you as it did for me. Cheers!
\Lua state\GUI\~GalaxyMap\@PlanetListPanel.lua
Code: Select all
--buycost
local function project_buycost(planet)
local project_type,project_info = planet: project_info()
if not project_type
return 0
end
local hammer_cost = planet.current_production_cost
if not hammer_cost
return 0
end
local remaining = hammer_cost-planet.hammers-planet.overflow_hammers
remaining=max(0,remaining)
return remaining * planet.empire.coins_to_labor_rate
end
--buycost.end
--projectgroup
local function project_group(planet)
return string.sub(planet.project_name,1,10) --returns 1st 10 chars of project_name
end
--projectgroup.end
function sort_funs.Activity (p1,p2)
return lexical_compare(
project_rank(p2),project_rank(p1),
p2.project_type, p1.project_type, --changed
project_group(p1), project_group(p2), --replaced planet.project_name
project_buycost(p1),project_buycost(p2), --replaced eq_project_rank()
p1.name , p2.name,
p2.outpost and 0 or total_pop(p2), p1.outpost and 0 or total_pop(p1),
p1._ikey, p2._ikey)
endend